[tex]\displaystyle\bf\\a)\\\\\left(\frac{1}{2}+\frac{3}{95}+\frac{4}{37}\right):\left(-\frac{1}{2}-\frac{3}{95}-\frac{4}{37}\right)=\\\\\text{Dam factor comun pe minus in a 2-a paranteza.}\\\\=\left(\frac{1}{2}+\frac{3}{95}+\frac{4}{37}\right):\left[-\left(\frac{1}{2}+\frac{3}{95}+\frac{4}{37}\right)\right]=\\\\\\=-\left(\frac{1}{2}+\frac{3}{95}+\frac{4}{37}\right):\left(\frac{1}{2}+\frac{3}{95}+\frac{4}{37}\right)=\\\\\\=\boxed{\bf-1}~~\text{ deoarece cele 2 paranteze sunt identice.}[/tex]
