Explicație pas cu pas:
5n+14/2n-7 €Z <=> 2n-7|5n+14
Avem:
2n-7|5n+14=> 2n-7|10n+28 (5n+14 /×2)
2n-7|2n-7=>2n-7|10n-35(2n-7 /×5)
Scadem si avem:
2n-7|10n+28-10n+35=> 2n-7|63 =>
2n-7€D63 in Z=>
2n-7€{-63,-21,-9,-7,-3,-1,1,3,7,9,21,63} =>
2n€{-54,-14,-2,0,4,6,8,10,14,16,28,70} =>
n€{-27,-7,-1,0,2,3,4,5,7,8,14,35}
