Răspuns :
Avem triunghi ABC cu unghi drept in A
AM inaltime deci AM perpendicular pe BC
Aria=baza*inaltimea/2
Aria=BC*AM/2
2*aria=BC*AM
Aria=24=>
2*24=BC*AM
AM=4,8=>
48=4,8*BC=>BC=48:4,8=>BC=48:48/10=>BC=48*10/48=>BC=480/48=>BC=10
AM*BC=AB*AC
AM=4,8 si BC=10=>
4,8*10=AB*AC
48=AB*AC
aria tr dreptunghic poate fi exprimata in 2 moduri astfel incit sa ne avantajeze in rezolvarea acestei probleme.
1) A=[tex] \frac{ c_{1}c_{2} }{2} [/tex]=24⇒[tex] c_{2} c_{2} [/tex]=48
2) A=[tex] \frac{ i_{p} h}{2} [/tex]=24⇒[tex] i_{p} = \frac{48}{4,8} =10[/tex]
1) A=[tex] \frac{ c_{1}c_{2} }{2} [/tex]=24⇒[tex] c_{2} c_{2} [/tex]=48
2) A=[tex] \frac{ i_{p} h}{2} [/tex]=24⇒[tex] i_{p} = \frac{48}{4,8} =10[/tex]