Răspuns :
[tex]\it (x+1)^2=x^2+x+8 \Rightarrow (x+1)^2 =x(x+1) +8 \Rightarrow (x+1)^2-x(x+1)=8 \Rightarrow\\ \\ \Rightarrow (x+1)(x+1-x)=8 \Rightarrow x+1=8 \Rightarrow x=7[/tex]
[tex]\it (x+1)^2=x^2+x+8 \Rightarrow (x+1)^2 =x(x+1) +8 \Rightarrow (x+1)^2-x(x+1)=8 \Rightarrow\\ \\ \Rightarrow (x+1)(x+1-x)=8 \Rightarrow x+1=8 \Rightarrow x=7[/tex]