Vs = 1 L = 1000 mL, ro = p = 0,76 g/mL
Stim ca p = ms/Vs => ms = pxVs = 760 g sol etanol
Stim ca c% = mdx100/ms, c% = 94%
=> md = msxc%/100 = 760x94/100 = 714,4 g etanol
714,4 g m g
2C2H5OH ---> C4H6 + H2O + H2
2x46 54
=> 419,32 g C4H6 la un randament de 100% ... dar la 80%....?
419,32 g ............. 100%
a g ...................... 80% => a = 335,46 g C4H6