Răspuns :
[tex] {3}^{21} \times {5}^{21} - {15}^{21} = {(3 \times 5)}^{21} - {15}^{21} = {15}^{21} - {15}^{21} = 0[/tex]
[tex] {3}^{20} \times {2}^{20} - {6}^{23} \div {6}^{3} = {(3 \times 2)}^{20} - {6}^{23} \div {6}^{3} = {6}^{20} - {6}^{20} = 0[/tex]
[tex] {2}^{18} \times {12}^{18} \div ( {6}^{16} \times {4}^{16} ) = {24}^{18} \div {24}^{16} = {24}^{2} = 576[/tex]
[tex] {75}^{38} \div {25}^{38} - { ({3}^{19}) }^{2} = {3}^{38} - {3}^{38} = 0[/tex]
[tex] {26}^{27} \div {13}^{27} \div {2}^{ {5}^{2} } = {2}^{27} \div {2}^{25} = {2}^{2} = 4[/tex]
[tex] {10}^{64} \div {2}^{64} - {5}^{ {4}^{3} } = {5}^{64} - {5}^{64} = 0[/tex]
b) 3^20×2^20-6^23:6^3=
=(3×2)^20-6^23+3=
=6^20-6^20=
=0
c) 2^18×12^18:(6^16×4^16)=
=(2×12)^18:[(6×4)^16]=
=24^18:24^16=
=24^18-16=
=24^2=
=576
d) 75^38:25^38-(3^19)^2=
=(75:25)^38-3^19×2=
=3^38-3^38=
=0
e) 26^27:13^27:2^5^2=
=(26:13)^27:2^25=
=2^27:2^25=
=2^27-25=
=2^2=
=4
f)10^64:2^64-5^4^3=
=(10:2)^64-5^64=
=5^64-5^64=
=0
Explicație pas cu pas:
REGULI DE CALCUL CU PUTERI:
a^m×a^n=a^m+n
a^m:a^n=a^m-n
(a^m)^n=a^m×n
a^n×b^n=(a×b)^n
a^n:b^n=(a:b)^n