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Monmihaela
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3 la puterea 3 +405 la puterea 2+0 la puterea 16 +1 la puterea 2015

Răspuns :

0000000

[tex]3^3+405^2+0^{16}+1^{2015}= \\ 27+(400+5)(400+5)+0+1= \\ 27+400^2+5^2+2*400*5+0+1= \\ 28+160000+25+4000= \\ 53+164000=\boxed{ 164053}[/tex]

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