Răspuns :
[tex]\displaystyle\bf\\2^{30}=2^{3\times10}=\Big(2^3\Big)^{10}=8^{10}\\\\3^{20}=3^{2\times10}=\Big(3^2\Big)^{10}=9^{10}\\\\9^{10}>8^{10}\\\\\boxed{\bf3^{20}>2^{30}}\\\\\boxed{\text{\bf Cel mai mare este }~~\bf3^{20}}[/tex]
[tex]\displaystyle\bf\\2^{30}=2^{3\times10}=\Big(2^3\Big)^{10}=8^{10}\\\\3^{20}=3^{2\times10}=\Big(3^2\Big)^{10}=9^{10}\\\\9^{10}>8^{10}\\\\\boxed{\bf3^{20}>2^{30}}\\\\\boxed{\text{\bf Cel mai mare este }~~\bf3^{20}}[/tex]