Răspuns:
Explicație pas cu pas:
[tex]5^{x-3}-\sqrt{5}=0, 5^{x-3}=\sqrt{5}. 5^{x-3}=5^{\frac{1}{2}}, deci\\x-3=\frac{1}{2}, x=3+\frac{1}{2}=3\frac{1}{2}[/tex]
[tex]\it 5^{x-3} -\sqrt5= 0 \Rightarrow 5^{x-3}=\sqrt5 \Rightarrow [(\sqrt5)^2]^{x-3} =\sqrt5\Rightarrow\\ \\ \Rightarrow(\sqrt5)^{2x-6}=\sqrt5 \Rightarrow 2x-6=1 \Rightarrow2x=7 \Rightarrow x=\dfrac{7}{2} \Rightarrow x = 3,5[/tex]
