Răspuns:
Explicație pas cu pas:
(3⁴)³:(3⁵×3⁶)+3⁴×3⁵:3⁷
Avem (3⁴)³=3⁴׳=3¹²
(3⁵×3⁶)=3⁵+⁶=3¹¹
Si 3⁴×3⁵:3⁷=3⁴+⁵-⁷=3²
Deci ne rămâne...
3¹²:3¹¹+3²
calculam catul
3¹²-¹¹+3²=3¹+3²
calculam puterile
3+9
adunam numerele
12
[tex]( {3}^{4})^{3} \div ( {3}^{5} \times {3}^{6} ) + {3}^{4} \times {3}^{5} \div {3}^{7} = 12 \\ {3}^{4 \times 3} \div {3}^{5 + 6} + {3}^{4 + 5} \div {3}^{7} = 12 \\ {3}^{12} \div {3}^{11} + {3}^{9} \div {3}^{7} = 12 \\ {3}^{12 - 11} + {3}^{9 - 7} = 12 \\ {3}^{1} + {3}^{2} = 12 \\ 3 + 9 = 12[/tex]
Formule aplicate
[tex] {a}^{m} \times {a}^{n} = {a}^{m + n} \\ {a}^{m} \div {a}^{n} = {a}^{m - n} \\ ( {a}^{m} )^{n} = {a}^{m \times n} [/tex]