[tex]\Big||x+2|-5\Big| = 3 \\ \\ \Leftrightarrow \left[\begin{array}{lcl} |x+2|-5 = 3 \\\\ |x+2|-5 = -3\end{array}\right. \Leftrightarrow \left[\begin{array}{lcl} \left[\begin{array}{lcl}(x+2)-5 = 3\\-(x+2)-5 = 3 \end{array}\right.\\ \\ \left[\begin{array}{lcl}(x+2)-5 = -3\\-(x+2)-5 = -3 \end{array}\right.\end{array}\right.\Leftrightarrow[/tex]
[tex]\Leftrightarrow \left[\begin{array}{lcl} \left[\begin{array}{lcl}x=6\\x=-10\end{array}\right.\\ \\ \left[\begin{array}{lcl}x=0\\x = -4 \end{array}\end{array}\right| \Rightarrow x\in \{-10,-4,0,6\}[/tex]
Celălalt se rezolvă la fel.
