Răspuns:
2C₁₀ˣ<C₁₀ˣ⁻¹
2*10!/x!*(10-x)!<10!/(x-1)!*(10-(x-1))l:10!
2/x!*(10-x)!<1/(x-1)!(10-x+1)!
2/(x-1)!*x*(10-x)!<1/(x-1)!*(11-x)!
2/x*(10-x)!<1/(10-x)!*(11-x)
2/x<1/(11-x)=>
x/2>11-x
x>22-2x
x+2x.>22
x>22/3≈7,3=>
x∈{8,9,10....}
Explicație pas cu pas:
