Răspuns:
[tex]A = 2^{69}[/tex]
Explicație pas cu pas:
[tex]A = \Big(\frac{{(2^5)}^3}{{(2^3)}^4} + \frac{2^{10}}{3\cdot 2^5+2^5}\Big)\cdot (2^{13})^5\\ \\ A = \Big( \frac{2^{15}}{2^{12}} + \frac{2^{10}}{2^2\cdot 2^5}\Big)\cdot (2^{13})^5 \\ \\ A = \Big( 2^3 + 2^{10-7}\Big)\cdot 2^{65}\\ \\ A = \Big(2^3+2^3\Big)\cdot 2^{65}\\ \\ A = 2^4\cdot 2^{65} \\ \\ A = 2^{69}[/tex]
