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Ştiind ca a=10 și b=7 calculați: a) (2×a+3×b)×(a-b); b) (3×a-b)×(2×a+b); c) (a+b)×(2×a+5-3×b).​

Răspuns :

a = 10

b = 7

a)

( 2 × a + 3 × b ) × ( a - b ) =

( 2 × 10 + 3 × 7 ) × ( 10 - 7 ) =

( 20 + 21 ) × 3 =

41 × 3 = 123

b)

( 3 × a - b ) × ( 2 × a + b ) =

( 3 × 10 - 7 ) × ( 2 × 10 + 7 ) =

( 30 - 7 ) × ( 20 + 7 ) =

23 × 27 = 621

c)

( a + b ) × ( 2 × a + 5 - 3 × b ) =

( 10 + 7 ) × ( 2 × 10 + 5 - 3 × 7 ) =

17 × ( 20 + 5 - 21 ) =

17 × ( 25 - 21 ) =

17 × 4 = 68

Răspuns:

    a) 123

    b) 621

    c) 68

Explicație pas cu pas:

    a) (2 × 10 + 3 × 7) × (10 - 7) =

    (20 + 21) × 3

    41 × 3 = 123

    b) (3 × 10 - 7) × (2 × 10 + 7) =

    (30 - 7) × (20 + 7) =

    23 × 27 = 621

    c) (10 + 7) × (2 × 10 + 5 - 3 × 7) =

    17 × (20 + 5 - 21) =

    17 × (25 - 21) =

    17 × 4 = 68