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Răspuns :

Andrada1212
2^(-x) = 2^(x-2)
=> -x = x-2
=> -2x = -2
=> x = 1

3^x = 27^(2x-1)
=> 3^x = 3^(3•(2x-1))
=> x = 6x-3
=> 5x = 3
=> x = 3/5

16^x = 4^(3-x)
=> 4^(2x) = 4^(3-x)
=> 2x = 3-x
=> 3x = 3
=> x = 1

log2 (3-2x) = 1
=> 3-2x = 2
=> 2x = 1
=> x = 1/2

log3 (4+x) = 3
=> 4+x = 3^3
=> 4+x = 27
=> x = 23

log5 (3-2x) = 2
=> 3-2x = 5^2
=> 3-2x = 25
=> 2x = -22
=> x = -11

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