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Dutaradu08
a fost răspuns

calculati {2 x 3^2-3^2+3 x [3+3 x (3^3-3^5:3^3)]}:(2017^0+0^2017+2^1)=


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Răspuns :

Marandrada

{2×3²-3²+3×[3+3×(3^3-3^5:3^3)]}:(2017^0+0^2017+2^1)=

={2×9-9+3×[3+3×(27-3²)]}:(1+0+2)=

=[18-9+3×(3+3×18)]:3=

=[9+3×(3+54)]:3=

=(9+3×57):3=

=(9+171):3=

=180:3=

=60

{2×3²-3²+3×[3+3×(3³-3⁵:3³)]}:(2017⁰+0²⁰¹⁷+2¹)

{3²+3×[3+3×(27-3²)]}:(1+0+2)

{9+3×[3+3×(27-9)]}:3

[9+3×(3+3×18)]:3

[9+3×(3+54)]:3

(9+3×57):3

(9+171):3

180:3

60

Zi senină ! :)