[tex] \it a = | \sqrt{6} - 2 | + | \sqrt{6} - 3 | + | \sqrt{6} - 4| + | \sqrt{6} + 1 | = = > \\ a = \sqrt{6} - 2 - \sqrt{6} + 3 - \sqrt{6} + 4 + \sqrt{6} + 1 = \boxed{ 6} \\ \it b = \sqrt{( 2\sqrt{3} - 3)^{2} } + \sqrt{( \sqrt{3 } - 5)^{2} } + \sqrt{(2 - \sqrt{3} )^{2} } = = > \\ b = | 2\sqrt{3} - 3 | + | \sqrt{3} - 5 | + |2 - \sqrt{3} | = = > \\ \it b = 2\sqrt{3} - 3 - \sqrt{3} + 5 + 2 - \sqrt{3} = \boxed{4} \\ \it a = 6; \: \: \: \: \: b = 4 = = > \: \: \boxed{a > b}[/tex]
