Răspuns :
[tex](3\sqrt{3} +2\sqrt{2})^{2} -(2\sqrt{3}-3\sqrt{2})^{2} -(\sqrt{3}-2\sqrt{2})(\sqrt{3}+2\sqrt{2})=\\=27+12\sqrt{6} +8-(12-12\sqrt{6}+18 )-(3-8)\\=27+12\sqrt{6}+8-12+12\sqrt{6}-18-3+8\\=10+24\sqrt{6} \\=2(5+12\sqrt{6} )[/tex]
[tex](3\sqrt{3} +2\sqrt{2})^{2} -(2\sqrt{3}-3\sqrt{2})^{2} -(\sqrt{3}-2\sqrt{2})(\sqrt{3}+2\sqrt{2})=\\=27+12\sqrt{6} +8-(12-12\sqrt{6}+18 )-(3-8)\\=27+12\sqrt{6}+8-12+12\sqrt{6}-18-3+8\\=10+24\sqrt{6} \\=2(5+12\sqrt{6} )[/tex]