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a fost răspuns

lim x-> infinit [tex]e^{x}[/tex] ( [tex]x^{2}[/tex] +4x + 1 )

Răspuns :

Rayzen

[tex]\lim\limits_{x\to \infty }\Big[e^x(x^2+4x+1)\Big] =\\ \\ =\lim\limits_{x\to \infty}e^x\cdot \lim\limits_{x\to \infty}(x^2+4x+1) = \infty \cdot \infty = \infty[/tex]