Acest exercițiu vă rog!

Răspuns:
a)[(7^2-3^2)]:5-2^29•2^27•2]•2017=[(49-9):5-2^29-27•2]•2017=
=(40:5-2^2•2)•2017=
=(8-4•2)•2017=
=(8-8)•2017=
=0•2017=
=0
b)(5^26•5^32):5^56-(2^5)^10:(2^6)^8=
=(5^26+32):5^56-(2)^5+10:(2)^6+8=
=5^58:5^56-2^15:2^14=
=(5)^58-56-(2)^15-14=
=5^2-2^1=
=25-2=
=3