a)
Cl2 + 2NaOH => NaCl + NaOCl + H2O
b)
59,6 g NaOCl s-au obtinut la rand. = 80%,
dar la 100% cat s-ar fi obtinut....?
59,6 g ....................... 80%
a g ............................. 100%
a = 74,5 g NaOCl
m g 74,5 g
Cl2 + 2NaOH => NaCl + NaOCl + H2O
2x40 74,5
=> m = 2x40x74,5/74,5 = 80 g NaOH