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5(x-2)-3≤[tex] \frac{9(x-2)}{2} -3(2x-4)[/tex]

Răspuns :

Miky93
5x-10-3≤9x-18/2   -6x +12   aducem la acelasi numitor
10x-20-6 ≤9x-18 -12x +24
10x-26 ≤-3x+6
10x+3x ≤6+26
13x<32
x≤ 32/13
5x-10-3≤(9x-18)/2-6x+12
5x+6x≤(9x-18)/2+12+13
11x-(9x-18)/2≤25 aducem la acelasi numitor
(22x-9x+18)/2≤25
13x≤25·2
x≤50/13

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