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SImplificati raportul: (2x-3)*2-1/2x2-4x+2
(*=la puterea, /=supra)

Răspuns :

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[tex] \frac{(2x-3)^2-1}{2x^2-4x+2}= \frac{(2x-3+1)(2x-3-1)}{2x^2-2x-2x+2}= \frac{(2x-2)(2x-4)}{2x(x-1)-2(x-1)}= \frac{2(x-1)*2(x-2)}{2(x-1)(x-1)}= \\ \\ = \boxed{\frac{2(x-2)}{x-1}} [/tex]

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