Răspuns :
1)
[tex] \sqrt{a(a+1)(a+2)(a+3)+1} =\\ \\ = \sqrt{a(a+3)(a+1)(a+2)+1} = \\ \\ = \sqrt{(a^2+3a)\Big((a^2+3a)+2\Big)+1} =\\ \\ = \sqrt{(a^2+3a)^2+2(a^2+3a)+1} = \\ \\ =\sqrt{(a^2+3a+1)^2} = \\ \\ =a^2+3a+1 \in \mathbb{N}[/tex]
1)
[tex] \sqrt{a(a+1)(a+2)(a+3)+1} =\\ \\ = \sqrt{a(a+3)(a+1)(a+2)+1} = \\ \\ = \sqrt{(a^2+3a)\Big((a^2+3a)+2\Big)+1} =\\ \\ = \sqrt{(a^2+3a)^2+2(a^2+3a)+1} = \\ \\ =\sqrt{(a^2+3a+1)^2} = \\ \\ =a^2+3a+1 \in \mathbb{N}[/tex]