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(√3-2)x < 2√2-4
(√5-2)x+3√5≥6
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Răspuns :

(√3-2)x<2√2-4
x<(2√2-4)/(√3-2)    rationalizam
x<[(2√2-4)(√3+2)]/(3-4)
x<[2√6+4√2-4√3-8]/-1
x<-2(√6+2√2-2√3-4)

(√5-2)x≥6-3√5
x≥(6-3√5)/(√5-2)             rationalizam
x≥[(6-3√5)(√5+2)]/(5-4)
x≥(6√5+12-15-6√5)
x≥-3
x∈[-3,+α)

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