C6H5-CH3 + Cl2 --h.niu--> C6H5-CH2Cl + HCl
C6H5-CH3 + Cl2 --AlCl3/intuneric--> Cl-C6H5-CH3 + HCl
p-clorotoluen
C6H5-CH3 + Cl2 --AlCl3/intuneric--> Cl-C6H5-CH3 + HCl
o-clorotoluen
1) reactie de substitutie la catena laterala
2) 1) reactie de substitutie la inelul aromatic
la 90% am obtinut 506 kg A
la 100% ..................... a = 562,22 kg A
m kg 562,22 kg
C6H5-CH3 + Cl2 --h.niu--> C6H5-CH2Cl + HCl
92 126,5
=> m = 408,88 kg toluen
ro p = m/V => V = m/p
=> V = 408,88 / 0,87 = 470 kg toluen
