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Nechitamagdale
a fost răspuns

Descompuneti in factori
a) x²+12x+35
b) x²+17x+70
c) x²+15x+56

Răspuns :

Angelicus
a) =x²+5x+7x+35=(x²+5x)+(7x+35)=x(x+5)+7(x+5)=(x+7)(x+5)

b) =x²+10x+7x+70=(x²+10x)+(7x+70)=x(x+10)+7(x+10)=(x+7)(x+10)

c) =x²+7x+8x+56=(x²+7x)+(8x+56)=x(x+7)+8(x+7)=(x+8)(x+7)

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