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Determinati numerele intregi x,y astfel incT (x+3)(y-1)=5

Răspuns :

Kawaiimath

(x+3)(y-1)=5

=> (x+3),(y-1)∈{(1,5),(-1,-5)}

x+3=1 =>x=-2

y-1=5 =>y=6

x+3=-1 =>x=-4

y-1=-5 => y=-4

=> (x,y) ∈ {(2,6),(-4,-4)}

Succes

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