a)
Pitagora
AM = √AB² + BM² = √12² + 5² = √144 + 25 = √169 = 13 dam
(BM = BC/2 = 5 dam)
b)
AC = √AB² + BC² = √144 + 100 = √244 = 2√61 cm
AO = AC/2 = √61 cm
OM = √OB² - BM² = √61 - 25 = √36 = 6 cm
c)
DCMO = trapez (OM || DC)
A(DCMO) = (OM+DC)/2 × MC = (6+12)/2 × 5 = 45 cm²