ABCD = trapez isoscel ortodiagonal =>
Lm = h
Duc CE ⊥ AB
Lm = (B + b)/2 = (36 + 12)/2 = 48/2 = 24 cm = CE
EB = (AB - CD)/2 = (36 - 12)/2 = 24/2 = 12 cm
Pitagora
BC = √CE² + EB² = √576 + 144 = √720 = 12√5 cm
ABCD = isoscel => BC = DA
P = AB + BC + CD + DA = 36 + 12 + 24√5 = 48 + 24√5 = 24(2 + √5) cm
