Răspuns:
Muchia laterala^2=ap^2+l^2/4
Ml^2=5^2+8^2/4
Ml^2=25+16
Ml^2=41
Ml=√41
Apotema bazei am calculat-o: ap=4
Aria bazei= l^2=8^2=64
Acum aflam aria lterala:
Perimetrul bazei=4l=4*8=32
Al=(Pb*ap)/2=(32*5)/2=160/2=80
Acum calculam Aria totala care este:
At=Al+Ab= 80+64=144
Acum aflam inaltimea:
ap^2=h^2+ab^2
ab=l/2=4
5^2=h^2+4^2
25=h^2+16
h^2=25-16=9
h=√9=3
Explicație pas cu pas: