Răspuns:
Explicație pas cu pas:
a)V=H/3(Ab+AB+√AB×Ab) 59904=h/3(80²+32²+80×32)
59904=h/3(6400+1024+2560) 59904=h/3×9984 6=h/3
h=18
in trapezul dreptunghic OPP'O' ducem inalt din P'
PP'²=MP²+H² PP'²=18²+32²=900 PP'=30=apotema trunchi
b)At=Al+AB+Ab
Al=4(80+32)30/2=112×60=6720 cm²
AB=80²=6400
Ab=32²=1024cm²
At=6720+6400+1024=14144cm²
c)Raportul de asemanare este 32/80=8/10=4/5
VO'/VO=4/5 x-18/x=4/5 x=inalt piramidei
5x-5×18=4x x=90 cm
V =VO×AB/3 V=90×6400/3=6400×30=192000cm³
Al pir mica/Al piram mare=16/25 ( Al piram mare-Al pir mica)/Al piram=25-16/25 Al trunchi/Al piram mare=9/25 6720/Al piram mare=9/25
Al piram mare=6720×25/9=746,66×25=18666,66 cm²
