210g xg yg
MgCO3 = MgO + CO2
84g 40g 44g
x=210 . 40 : 84=100 g MgO [ n=100g : 40g/moli=2,5 moli MgO ]
y=210.44 : 84=110 g CO2 [ 110g : 44g/moli=2,5 moli CO2 ]
MCaO=40 +16=56------>56 g/moli CaO
MCO2=12 +2.16=44-------> 44g/moli
MMgCO3=40+12 +3.16=84------> 84g/moli