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(rad 5-rad 3)^2= ;(rad 5-rad 2)•(rad5+rad2)=​

Răspuns :

Maverickarcher

(√5-√3)² = √5²-2*√5*√3 + √3² = 5-2√15 + 3 = 8-2√15

Am aplicat formula (a-b)² = a²-2ab+b² si m-am folosit de proprietatile radicalilor.

(√5-√2)(√5+√2) = √5²-√2² = 5-2 = 3

Am aplicat formula (a-b)(a+b) = a²-b².

Nicumavro
a. √5-√3)^2=5-2√15+3=8-2√15
b. (√5-√2)(√5+√2)=5-2=3
am aplicat
(a-b)^2=a^2-2ab+b^2
(a+b)(a-b)=a^2-b^2

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