[tex]0.5 + \frac{4}{33} \times ( - 0.25 + \frac{131}{2} ) = \frac{1}{2} + \frac{4}{33} \times ( - \frac{1}{4} + \frac{131}{2} ) = \frac{1}{2} + \frac{4}{33} \times \frac{261}{4} = \frac{1}{2} + \frac{1}{11} \times 87 = \frac{1}{2} + \frac{87}{11} = \frac{185}{22} [/tex]
