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a) (6x²-6x):(x-1)
b) (4x+1)²:(4x+19)
c) (2x-5)²:(2x-5)
d) [(8x²+6x)(5x-1)]:(4x+3)

Răspuns :

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a) (6[tex] x^{2} [/tex]-6x):(x-1)=
=6x(x-1):(x-1)=
=6x

b) [tex] (4x+1)^{2} [/tex]:(4x+1)=4x+1

c) [tex] (2x-5)^{2} [/tex]:(2x-5)=2x-5

d) [(8[tex] x^{2} [/tex]+6x)(5x-1)]:(4x+3)=
=[2x(4x+3)(5x-1)]:(4x+3)=
=2x(5x-1)


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