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paralelpiped dr.
L = 2radical3 cm
l=2 cm
h=4radical3cm

v=?
At=?
dpar.=?

Răspuns :

 [tex]V=L*l*h=2\sqrt3\cdot2\cdot4\sqrt3=2*2*4*3=48cm^3\;;\\ A_t=A_l+2*A_b=\\ =P_b+2*A_b=2(2+\sqrt3)*4\sqrt3\;+\;2*(2*2\sqrt3)=\\ =16\sqrt3+24\,+\,8\sqrt3=24\sqrt3+24 = ...=\\ d=\sqrt{L^2+l^2+h^2}= .... =\sqrt{12+4+48}=8cm\;; [/tex]

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