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ms1=400g HCl
C1=10%
+
ms2=400g HCl
C2=5%
+
mH2O=200g

sa se afle concentratia procentuala finala. va rog frumos ma ajutati? ma rog. cine e on-line la ora asta

Răspuns :

Roberteladrianpb6zy7

ms1=400g HCl

C1=10%

+

ms2=400g HCl

C2=5%

+

mH2O=200g

stim ca c% = mdx100/ms => md = msxc%/100

=> md1 = ms1xc1/100 = 400x10/100 = 40 g

md2 = ms2xc2/100 = 400x5/100 = 20 g

md.tot = md1+md2 = 40+20 = 60 g

ms.tot = ms1+ms2+m.apa = 400+400+200 = 1000 g

=> c%.final = md.totx100/ms.tot

= 60x100/1000 = 6%

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