Răspuns:
Explicație pas cu pas:
[tex]\it \dfrac{25}{14}\cdot\Big(\dfrac{2}{5}\Big)^2+\dfrac{22}{21}=\dfrac{25}{14}\cdot\dfrac{4}{25}+\dfrac{22}{21}=\dfrac{^{3)}2}{\ 7}+\dfrac{22}{21} =\dfrac{6+22}{21}=\dfrac{\ 28^{(7}}{21}=\dfrac{4}{3}=1\dfrac{1}{3}[/tex]
