Răspuns:
Explicație pas cu pas:
ma(a,b,c) = (a+b+c)/3 =?
ma(a,b) = 11 => (a+b)/2 = 11 => a+b = 22 (1)
ma(a,c) = 36 => (a+c)/2 = 36 => a+c = 72 (2)
ma(b,c) = 32 => (b+c)/2 = 32 => b+c = 64 (3)
(1)+(2) => 2a+(b+c) = 22+72 => 2a+64 =94 => 2a = 94-64
2a = 30 => a = 15
b = 22-a => b = 22-15 => b = 7
c = 72-a => c = 72-15 => c = 57
a+b = 15+7 = 22
a+c = 15+57 =72
b+c = 7+57 = 64
(a+b+c)/3 = (15+7+57)/3 = 79/3 = 26,(3)
