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Cochiortiberiu
a fost răspuns

Simplificati fractiile urmatoare pana cand optineti fractii ireductibile.

a)4supra32;18supra24;95supra125;44supra121;36supra60;18supra12;7a supra5a;2(x+1)supra4(x+1);2⁴·5³·7³supra2³·5⁴·7;

b)3²supra3·5 ;2²·3supra2⁵·3²;2·3·5³supra2·3²·5;5²·7³·11⁴supra3⁵·7³·11²;144supra7²·12;13²·17⁴·19supra13²·17³·23;5¹¹:5⁶·3:3supra5³·5²·3²·7.
cand ziceam supra ma refeream ca e una sub alta cum ar fi 2sub3 cand ziceam supra adica pui primul numar care lam zis sub care am zis dupa supra

ajutatima repede va rog foarte frumos

Răspuns :

Emy78
4/32=1/8
18/24=3/4
95/125=19/25
44/121=4/11
36/60=6/10=3/5
18/12=3/27
a/5a=7/5
[2(x+1)]/[4(x+1)]=2/4=1/2
(2^4·5^3·7^3)/(2³·5^4·7)=2·7²/5=98/5

b. 3²/(3·5)=3/52²·3/(2^5·3²)=1/(2³·3)=1/24
2·3·5³/(2·3²·5)=5²/3=25/3
5²·7³·11^4/(3^5·7³·11²)=5²·11²/3^5=25·121/243=3025/243
144/(7²·12)=12/29
17·19/23=323/23
5^5·1/(5^5·3²·7)=1/(9·7)=1/63