Răspuns :
M,MgO= 40g/mol
M,MgCO3= 84g/mol
M,Mg(OH)2= 68g/mol
a)
1mol.................1mol sau, in grame
MgCO3-----> MgO +CO2
84g.......................40g
x..................................8ookg
x=m= 1680kg MgCO3 PUR
p= m,px100/mi---> m,i= 1680x100/80=........................calculeaza !!!!
b) 1mol.....................1mol
MgO + H2O---> Mg(OH)2
40g.....................68g
800kg......................x=m=1360kg
c) 84g MgCO3..........24gMg........12gC..........3x16gO
100G.....................................x...............y...............z
calculeaza x,y,z !!!!!