y=2x+1
y=x^2-x+3
x^2-x+3=2x+1
scazi 2x
x^2-3x+3=1
scazi 1
x^2-3x+2=0
x^2-2x-x+2=0
x(x-2)-(x-2)=0
(x-1)(x-2)=0
ai 2 cazuri:
x-1=0
x=1
sau
x-2=0
x=2
deci ai 2 variante de y:
y=2 ori 1+1
y=3
y=2 ori 2+1
y=5
solutille (x,y) sunt:{ (1,3) ; (2,5) }
