Z=30----> Zn
Z=35------> Br
-react. numai din 70% din 6,5 kg Zn
100kg---------70 kg
6,5kg----------xkg
x=6,5 .70 : 100=4,55kg Zn
-se scrie ec. reactiei
-se afla masa de ZnBr2
4,55kg ykg
Zn + Br2= ZnBr2
65kg 225kg
y=4,55 .225 : 65=15,75 kg ZnBr2
n=m;M
n= 15,75 kg : 225 kg/kmoli=0,07 kmoli ZnBr2
MZnBr2=65 + 2.80=225-------> 225kg/kmoli
