- se calculeaza masa molara
MH2O=2+ 16=18---------> 18g/moli
18g H2O-----------16g O
36g H2O---------------xg O
x-36.16 : 18=32 g O
MH2SO4=2+32+4.16=98------->98g/moli
mH2SO4= 2moli . 98g/moli=196 g
98g H2SO4 ---------64g O
196g------------------------y
y=196.64 :98=128 g O
0,15 kmoli=150moli SO2
M=32+ 2.16=64--------->64g/moli
64g SO2---------------32g O
150moli----------------------z
z=150.32 : 64=75 g O
g H2O
6g H
M=2+16=18-------->18g/moli
18 g H2O------------------2g H
xg-----------------------------6g H
x=18 .6 : 2=54 g H2O
g PH3
6g H
M=31 + 3=34--------> 34g/moli
34g-----------3g H
y g ---------------6gH
y= calculeaza !!!!!!!!!!!!!!!!!!
gH2CO3
6gH
M=2+12 +3.16=62-------->62 g /moli
62g H2CO3--------------2g H
zg-----------------------------6gH
z=calculeaza !!!!!!!!!!!!
