m,anilina=v x ro= 455mlx1,022g/ml=> 465g
M,anilina= 93g/mol
M,compus final= 197g/mol
din reactia
1mol.......................................1mol
C6H5-COCl+ C6H5-NH2---> C6H5-NH-CO-C6H5 + HCl
93g anilina.........197g compus final
465g,,,,,,,,,,,,,,,,,,,,,,,,,,m,teoretica=985g
m,practica= 935,75g < m teoretica
randamentul =935,75x100/985= .........................calculeaza !!!!!