Răspuns :
1,(6)=(16-1)/9=15/9=5/3
0,(3)=3/9=1/3
a+b=5/3
a-b=1/3=>a=1/3+b
Inlocuim in prima:
1/3+b+b=5/3
1/3+2b=5/3
2b=5/3-1/3
2b=4/3
b=4/3*1/2=4/6=2/3
a=1/3+2/3=1
0,(3)=3/9=1/3
a+b=5/3
a-b=1/3=>a=1/3+b
Inlocuim in prima:
1/3+b+b=5/3
1/3+2b=5/3
2b=5/3-1/3
2b=4/3
b=4/3*1/2=4/6=2/3
a=1/3+2/3=1
Fie a,b cele doua numere reale
a+b=1,(6)
a-b=0,(3) ⇒ a=0,(3)+b
⇒ 3/9+b+b=15/9
1/3+2b=5/3
2b=5/3-1/3
2b=4/3
b=4/3·1/2
b=2/3
⇒ a=3/9+2/3
a=1/3+2/3
a=3/3
a=1
Sper ca te-am ajutat :)
a+b=1,(6)
a-b=0,(3) ⇒ a=0,(3)+b
⇒ 3/9+b+b=15/9
1/3+2b=5/3
2b=5/3-1/3
2b=4/3
b=4/3·1/2
b=2/3
⇒ a=3/9+2/3
a=1/3+2/3
a=3/3
a=1
Sper ca te-am ajutat :)