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a fost răspuns

Calculati :
a) (7 supra 8 + 5 supra 6 )* 24 supra 41
b) (3 supra 4 - 1 supra 2 ) : 1 supra 8
c) media ponderata a numerelor a= 4,2 si b= 3,5(3) cu ponderile 7 si 3...
Va rog urgentt ...

Răspuns :

a)(7/8+5/6)x24/41=
[(7x3+5x4)/24]x24/41=simplif.cu 24
(21+20)/41=41/41=1

b)(3/4-1/2):1/8=
[(3-2)/4]x8=8/4=2

c)b=(353-35)/90=318/90=simplif.cu 2=159/45= simplif.cu 3=53/15
a=42/10=21/5
Mp=(7x21/5+3x53/15)/(7+3)=(147/5+159/15)/10=[147x3+159)/15]/10=
=600/150=4
Mp=4

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