a=primul bambar
b=al doilea hambar
c=al treilea hambar
a+b+c=164,68
a=a
b=a+2,18
c=a+2.18+3,78(5.96)
164,68=a+a+2.18+a+5.96 (5.96+2.18=8.14)
164.68-8.14=3a
a=156.54:3
a=52.28
b=a+2.18=52.28+2.18=54.56
c=a+5.96=52.28+5.96=58.24
verificam:a+b+c=164.68
52.28+54.56+58.24=164.68