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Paulbohatel
a fost răspuns

(radical din2 )^6-(1supra2)^3-(radical din 25 supra 2)^6 :(5 supra radical din 2)^4 ori radical 16 supra 25

Răspuns :

DanielaBalan

[tex]( \sqrt{2} ) {}^{6} - ( \frac{1}{2}) {}^{3} - ( \frac{ \sqrt{25} }{2} ) {}^{6} \div ( \frac{5}{ \sqrt{2} } ) {}^{4} \times \frac{ \sqrt{16} }{25} = {2}^{3} - \frac{1}{27} - ( \frac{5}{2} ) {}^{6} \div \frac{625}{4} \times \frac{4}{25} = 8 - \frac{1}{27} - \frac{15625}{64} \times \frac{4}{625} \times \frac{4}{25} = 8 - \frac{1}{27} - \frac{25}{16} \times \frac{4}{25} = 8 - \frac{1}{27} - \frac{1}{4} = \frac{833}{108} [/tex]

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